Grade 12 Chemistry Questions and Answers
A free sample of Grade 12 Chemistry practice questions with the correct answer and an explanation, following the Lebanese curriculum. Useful for revision before school tests.
أسئلة الكيمياء للصف 12 مع الأجوبة والشرح وفق المنهج اللبناني.
How to use this page: read each question, try to answer it yourself, then open the answer to check your reasoning. Questions are grouped by the chapter they belong to on EduRise, in the order of the Lebanese Grade 12 Chemistry programme.
15 Grade 12 Chemistry practice questions
Chapter: The Gaseous State · easy
1. A gas thermometer reads T = 294 K. What is the Celsius temperature?
- A. 294 °C
- B. −21 °C
- C. 567 °C
- D. 21 °C
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Answer: 21 °C
Explanation: θ = T − 273 = 294 − 273 = 21 °C.
Chapter: The Gaseous State · easy
2. A gas thermometer reads T = 412 K. What is the Celsius temperature?
- A. 412 °C
- B. −139 °C
- C. 139 °C
- D. 685 °C
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Answer: 139 °C
Explanation: θ = T − 273 = 412 − 273 = 139 °C.
Chapter: Rate of Reactions · easy
3. The unit mol·L⁻¹·min⁻¹ is the unit of:
- A. a concentration
- B. an amount of matter
- C. a volumetric rate
- D. a half-life time
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Answer: a volumetric rate
Explanation: Volumetric rate = change of concentration per unit time.
Chapter: Rate of Reactions · easy
4. For 2 MnO₄⁻ + 5 H₂C₂O₄ + 6 H₃O⁺ → 2 Mn²⁺ + 10 CO₂ + 14 H₂O, n₀(MnO₄⁻) = 3.0 mmol. At time t, n(MnO₄⁻) = 1.0 mmol. What amount of Mn²⁺ has been formed (none initially)?
- A. 1.00 mmol
- B. 2.00 mmol
- C. 4.00 mmol
- D. 8.00 mmol
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Answer: 2.00 mmol
Explanation: n(MnO₄⁻) = n₀ − 2x → x = (3.0 − 1.0)/2 = 1.00 mmol; n(Mn²⁺) = 2x = 2.00 mmol.
Chapter: Kinetic Factors · easy
5. Why does zinc powder react faster with acid than a zinc piece of the same mass?
- A. the powder has a larger contact surface
- B. the powder raises the temperature
- C. the powder is a catalyst
- D. the powder contains more zinc
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Answer: the powder has a larger contact surface
Explanation: A solid reacts at its surface; dividing it increases the surface in contact with the acid.
Chapter: Kinetic Factors · easy
6. What type of catalysis is it: a slice of raw potato (containing catalase) dropped into hydrogen peroxide?
- A. heterogeneous catalysis
- B. enzymatic catalysis
- C. no catalysis: it is a reactant
- D. homogeneous catalysis
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Answer: enzymatic catalysis
Explanation: Catalase is an enzyme (a protein): enzymatic catalysis.
Chapter: Chemical Equilibrium · easy
7. The equilibrium constant Kc depends only on:
- A. the presence of a catalyst
- B. the temperature
- C. the initial amounts
- D. the volume of the mixture
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Answer: the temperature
Explanation: Kc is fixed at a given temperature.
Chapter: Chemical Equilibrium · easy
8. What is the expression of the equilibrium constant of Fe³⁺ + SCN⁻ ⇌ FeSCN²⁺?
- A. Kc = [FeSCN²⁺]/([Fe³⁺] + [SCN⁻])
- B. Kc = [FeSCN²⁺][Fe³⁺][SCN⁻]
- C. Kc = [FeSCN²⁺]/([Fe³⁺][SCN⁻])
- D. Kc = [Fe³⁺][SCN⁻]/[FeSCN²⁺]
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Answer: Kc = [FeSCN²⁺]/([Fe³⁺][SCN⁻])
Explanation: Kc = products/reactants at equilibrium, each to the power of its coefficient (here 1).
Chapter: pH. Strong Acid, Strong Base. pH-metric Titration · easy
9. The pH meter reads pH = 6.49 at 25 °C. What is [H₃O⁺] in the solution?
- A. 3.2 × 10⁻⁷ mol/L
- B. 3.1 × 10⁻⁸ mol/L
- C. 1.5 × 10⁻³ mol/L
- D. 3.2 × 10⁻⁶ mol/L
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Answer: 3.2 × 10⁻⁷ mol/L
Explanation: [H₃O⁺] = 10⁻ᵖᴴ = 10^(−6.49) = 3.2 × 10⁻⁷ mol/L.
Chapter: pH. Strong Acid, Strong Base. pH-metric Titration · easy
10. At 25 °C, a solution has [H₃O⁺] = 6.0 × 10⁻⁵ mol/L. What is its pH?
- A. 9.78
- B. 5.78
- C. 4.22
- D. 5.22
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Answer: 4.22
Explanation: pH = −log[H₃O⁺] = −log(6.0 × 10⁻⁵) = 4.22: the solution is acidic.
Chapter: Weak Acid, Weak Base, Conjugate Acid/Base Pair · easy
11. The acid constant of a pair is Ka = 2.5 × 10⁻¹⁰ at 25 °C. What is its pKa?
- A. 4.40
- B. 10.60
- C. 10.00
- D. 9.60
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Answer: 9.60
Explanation: pKa = −log Ka = −log(2.5 × 10⁻¹⁰) = 9.60.
Chapter: Weak Acid, Weak Base, Conjugate Acid/Base Pair · easy
12. What is the conjugate base of NH₄⁺?
- A. NH₃
- B. CH₃COO⁻
- C. NH₄⁺
- D. HCOO⁻
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Answer: NH₃
Explanation: The conjugate base is obtained by removing one H⁺: NH₄⁺ ⇌ NH₃ + H⁺; the pair is NH₄⁺/NH₃.
Chapter: Reaction between a Weak Acid and a Strong Base · easy
13. Which equation describes the titration of ammonia by hydrochloric acid?
- A. NH₄⁺ + OH⁻ → NH₃ + H₂O
- B. NH₃ + H₂O ⇌ NH₄⁺ + OH⁻
- C. NH₃ + H₃O⁺ → NH₄⁺ + H₂O
- D. H₃O⁺ + OH⁻ → 2 H₂O
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Answer: NH₃ + H₃O⁺ → NH₄⁺ + H₂O
Explanation: The base NH₃ reacts with the strongest acid present, H₃O⁺; the reaction is complete (K = 10⁹·²).
Chapter: Reaction between a Weak Acid and a Strong Base · easy
14. During the titration of a weak acid by sodium hydroxide, V_bE = 10.0 mL. At what volume of base is pH = pKa?
- A. 5.0 mL
- B. 10.0 mL
- C. 2.5 mL
- D. 20.0 mL
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Answer: 5.0 mL
Explanation: pH = pKa at half-equivalence, V_bE/2 = 10.0/2 = 5.0 mL, where n(HA) = n(A⁻).
Chapter: Functional Groups · easy
15. Which functional group characterises the carboxylic acids?
- A. carbonyl group inside the chain, –CO–
- B. hydroxyl group –OH
- C. carboxyl group –COOH
- D. carbonyl group at the end of the chain, –CHO
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Answer: carboxyl group –COOH
Explanation: Carboxylic acid: carboxyl group –COOH; name ending -oic acid.
More practice
These are sample questions only. The full Grade 12 Chemistry course on EduRise includes every chapter, lessons, 1,664 questions and timed exams.
Chemistry questions in other grades
Other Grade 12 subjects
See also: Grade 12 Chemistry chapters · All question pages · Study guides
About these questions
Where do these Grade 12 Chemistry questions come from?
They are a sample from EduRise's Grade 12 Chemistry question bank (1,664 questions across 16 chapters), written to follow the Lebanese curriculum. Each chapter on EduRise has its own practice set and a timed exam.
Are the answers explained?
Yes. Every question on EduRise shows the correct answer and an explanation after you answer, in practice mode and in the exam review.
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