أسئلة الكيمياء الصف الحادي عشر مع الحل

14 سؤالاً تدريبياً في الكيمياء – الصف الحادي عشر

1. الفصل: Oxidation Reduction Reactions · سهل

   1. The blue colour of a copper(II) sulfate solution is due to:

   • A. water molecules
   • B. copper atoms
   • C. the Cu²⁺ ions
   • D. the SO₄²⁻ ions
   أظهر الجواب ▾

   Answer: the Cu²⁺ ions

   Explanation: Cu²⁺(aq) is blue; SO₄²⁻ is colourless.

2. الفصل: Oxidation Reduction Reactions · سهل

   2. An oxidant is a species that:

   • A. loses protons
   • B. loses electrons
   • C. gains protons
   • D. gains electrons
   أظهر الجواب ▾

   Answer: gains electrons

   Explanation: The oxidant captures electrons and is reduced.

3. الفصل: Oxidation Reduction Potential · سهل

   3. In the external circuit, the current goes from the + pole to the − pole.

   • A. True
   • B. False
   أظهر الجواب ▾

   Answer: True

   Explanation: True: the current is opposite to the electrons, which go − → +.

4. الفصل: Oxidation Reduction Potential · سهل

   4. In a galvanic cell, oxidation takes place at:

   • A. the cathode
   • B. the salt bridge
   • C. the voltmeter
   • D. the anode
   أظهر الجواب ▾

   Answer: the anode

   Explanation: Anode = oxidation (− pole); cathode = reduction (+ pole).

5. الفصل: Balancing Oxidation Reduction Reactions · سهل

   5. The oxidation number of oxygen in most compounds is:

   • A. −1
   • B. −2
   • C. +2
   • D. 0
   أظهر الجواب ▾

   Answer: −2

   Explanation: O = −2 in oxides, water, ions such as SO₄²⁻; −1 only in peroxides.

6. الفصل: Balancing Oxidation Reduction Reactions · سهل

   6. Which couple contains iodine and iodide?

   • A. I/I₂
   • B. I₂/IO₃⁻
   • C. I⁻/I₂
   • D. I₂/I⁻
   أظهر الجواب ▾

   Answer: I₂/I⁻

   Explanation: Couples are written Ox/Red: I₂ is the oxidised form.

7. الفصل: Titration by Oxidation Reduction Reaction · سهل

   7. The colour of the first excess of permanganate in the Erlenmeyer is:

   • A. pink
   • B. blue
   • C. green
   • D. colourless
   أظهر الجواب ▾

   Answer: pink

   Explanation: Very dilute MnO₄⁻ looks pink.

8. الفصل: Titration by Oxidation Reduction Reaction · سهل

   8. At equivalence, C(Fe²⁺) × V(Fe²⁺) = C(MnO₄⁻) × V_E.

   • A. True
   • B. False
   أظهر الجواب ▾

   Answer: False

   Explanation: False: n(Fe²⁺) = 5 n(MnO₄⁻) from the balanced equation.

9. الفصل: Organic Compounds and Elemental Analysis · سهل

   9. In elemental analysis, how is the mass percentage of oxygen usually obtained?

   • A. from the mass of the CaCl₂ tube
   • B. from the mass of the KOH tube
   • C. by difference: %O = 100 − (%C + %H + …)
   • D. by weighing the oxygen released
   أظهر الجواب ▾

   Answer: by difference: %O = 100 − (%C + %H + …)

   Explanation: Oxygen has no simple direct test: it is the rest after the other elements are measured.

10. الفصل: Organic Compounds and Elemental Analysis · سهل

    10. Heated with soda lime, a compound releases a gas that turns moist red litmus paper blue. Which element does the compound contain?

    • A. chlorine
    • B. nitrogen
    • C. carbon
    • D. oxygen
    أظهر الجواب ▾

    Answer: nitrogen

    Explanation: The gas is ammonia NH₃ (basic), formed from the nitrogen of the compound.

11. الفصل: Alkanes · سهل

    11. Butane and 2-methylpropane are isomers.

    • A. True
    • B. False
    أظهر الجواب ▾

    Answer: True

    Explanation: True: both are C₄H₁₀ with different skeletons (chain isomers).

12. الفصل: Alkanes · سهل

    12. What is the general formula of the alkanes?

    • A. CₙHₙ₊₂
    • B. CₙH₂ₙ₊₂
    • C. CₙH₂ₙ₋₂
    • D. CₙH₂ₙ
    أظهر الجواب ▾

    Answer: CₙH₂ₙ₊₂

    Explanation: Alkanes contain only single bonds: CₙH₂ₙ₊₂ (methane CH₄, ethane C₂H₆).

13. الفصل: Alkenes · سهل

    13. Which catalyst is used for the hydrogenation of an alkene?

    • A. light
    • B. concentrated H₂SO₄
    • C. copper(II) oxide
    • D. nickel (Ni)
    أظهر الجواب ▾

    Answer: nickel (Ni)

    Explanation: CₙH₂ₙ + H₂ → CₙH₂ₙ₊₂ over heated nickel (or Pt).

14. الفصل: Alkenes · سهل

    14. The hydration of propene gives mainly propan-2-ol.

    • A. True
    • B. False
    أظهر الجواب ▾

    Answer: True

    Explanation: True: Markovnikov's rule — H goes to CH₂, OH to the middle carbon.

المزيد من التدريب

هذه عيّنة فقط. تشمل دورة الكيمياء الكاملة للصف الحادي عشر على EduRise كل الفصول والدروس و728 الأسئلة والامتحانات المؤقّتة.

أسئلة الكيمياء في صفوف أخرى

مواد أخرى في الصف الحادي عشر

اطّلع أيضاً على: فصول الكيمياء – الصف الحادي عشر · كل صفحات الأسئلة · المقالات الدراسية

عن هذه الأسئلة